What are the solutions to the equation -6x^2+7x=3x-8 ?

The solutions to the equation -6x^2+7x=3x-8 are x=-(-1+sqrt(13))/3 ,x=(1+sqrt(13))/3

Find the zeros of -6x^2+7x=3x-8

The zeros of -6x^2+7x=3x-8 are x=-(-1+sqrt(13))/3 ,x=(1+sqrt(13))/3

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- 6 x^{2} + 7 x = 3 x - 8

x = - \frac{- 1 + 13}{3}, x = \frac{1 + 13}{3}

Decimal Notation

x = - 0.86851 \dots, x = 1.53518 \dots

Solution steps

- 6 x^{2} + 7 x = 3 x - 8

Move

8

to the left side

- 6 x^{2} + 7 x + 8 = 3 x

Move

3 x

to the left side

- 6 x^{2} + 4 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 6 ) \cdot 8}{2 ( - 6 )}

4^{2} - 4 (- 6) \cdot 8 = 413

x_{1, 2} = \frac{- 4 \pm 4 13}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 4 + 4 13}{2 ( - 6 )}, x_{2} = \frac{- 4 - 4 13}{2 ( - 6 )}

x = \frac{- 4 + 4 13}{2 ( - 6 )} : - \frac{- 1 + 13}{3}

x = \frac{- 4 - 4 13}{2 ( - 6 )} : \frac{1 + 13}{3}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 13}{3}, x = \frac{1 + 13}{3}

- 6 x^{2} - 3 x + 6 = 0

x^{2} + 8 x + 15 = (x + 3)

(2 x + 3)^{2} = (x - 2)^{2}

x^{2} + 9^{2} = 1 2^{2}

9 x^{2} + 2 x = 2 x^{2} - 6 x

What are the solutions to the equation -6x^2+7x=3x-8 ?
The solutions to the equation -6x^2+7x=3x-8 are x=-(-1+sqrt(13))/3 ,x=(1+sqrt(13))/3
Find the zeros of -6x^2+7x=3x-8
The zeros of -6x^2+7x=3x-8 are x=-(-1+sqrt(13))/3 ,x=(1+sqrt(13))/3