What are the solutions to the equation -5m(8m-8)=120 ?

The solutions to the equation -5m(8m-8)=120 are m= 1/2-i(sqrt(11))/2 ,m= 1/2+i(sqrt(11))/2

Find the zeros of -5m(8m-8)=120

The zeros of -5m(8m-8)=120 are m= 1/2-i(sqrt(11))/2 ,m= 1/2+i(sqrt(11))/2

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- 5 m (8 m - 8) = 120

m = \frac{1}{2} - i \frac{11}{2}, m = \frac{1}{2} + i \frac{11}{2}

Solution steps

- 5 m (8 m - 8) = 120

Expand

- 5 m (8 m - 8) : - 40 m^{2} + 40 m

- 40 m^{2} + 40 m = 120

Move

120

to the left side

- 40 m^{2} + 40 m - 120 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 40 ) ( - 120 )}{2 ( - 40 )}

Simplify

4 0^{2} - 4 (- 40) (- 120) : 4011 i

m_{1, 2} = \frac{- 40 \pm 40 11 i}{2 ( - 40 )}

Separate the solutions

m_{1} = \frac{- 40 + 40 11 i}{2 ( - 40 )}, m_{2} = \frac{- 40 - 40 11 i}{2 ( - 40 )}

m = \frac{- 40 + 40 11 i}{2 ( - 40 )} : \frac{1}{2} - i \frac{11}{2}

m = \frac{- 40 - 40 11 i}{2 ( - 40 )} : \frac{1}{2} + i \frac{11}{2}

The solutions to the quadratic equation are:

m = \frac{1}{2} - i \frac{11}{2}, m = \frac{1}{2} + i \frac{11}{2}

35 x^{2} + 455 x + 1260 = 0

7 x^{2} - x - 1 = 0

\frac{t ^{2}}{3} - \frac{t}{6} = 1

x^{2} - 12 x = 64

x^{2} - 12 x = 14

What are the solutions to the equation -5m(8m-8)=120 ?
The solutions to the equation -5m(8m-8)=120 are m= 1/2-i(sqrt(11))/2 ,m= 1/2+i(sqrt(11))/2
Find the zeros of -5m(8m-8)=120
The zeros of -5m(8m-8)=120 are m= 1/2-i(sqrt(11))/2 ,m= 1/2+i(sqrt(11))/2