What are the solutions to the equation 7x^2-x-1=0 ?

The solutions to the equation 7x^2-x-1=0 are x=(1+sqrt(29))/(14),x=(1-sqrt(29))/(14)

Find the zeros of 7x^2-x-1=0

The zeros of 7x^2-x-1=0 are x=(1+sqrt(29))/(14),x=(1-sqrt(29))/(14)

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7 x^{2} - x - 1 = 0

x = \frac{1 + 29}{14}, x = \frac{1 - 29}{14}

Decimal Notation

x = 0.45608 \dots, x = - 0.31322 \dots

Solution steps

7 x^{2} - x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

(- 1)^{2} - 4 \cdot 7 (- 1) = 29

x_{1, 2} = \frac{- ( - 1 ) \pm 29}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 29}{2 \cdot 7}, x_{2} = \frac{- ( - 1 ) - 29}{2 \cdot 7}

x = \frac{- ( - 1 ) + 29}{2 \cdot 7} : \frac{1 + 29}{14}

x = \frac{- ( - 1 ) - 29}{2 \cdot 7} : \frac{1 - 29}{14}

The solutions to the quadratic equation are:

x = \frac{1 + 29}{14}, x = \frac{1 - 29}{14}

\frac{t ^{2}}{3} - \frac{t}{6} = 1

x^{2} - 12 x = 64

x^{2} - 12 x = 14

x^{2} = - 240 - 8

0 = 2 x^{2} - 6 x - 1

What are the solutions to the equation 7x^2-x-1=0 ?
The solutions to the equation 7x^2-x-1=0 are x=(1+sqrt(29))/(14),x=(1-sqrt(29))/(14)
Find the zeros of 7x^2-x-1=0
The zeros of 7x^2-x-1=0 are x=(1+sqrt(29))/(14),x=(1-sqrt(29))/(14)