What are the solutions to the equation 8p^2+56p+54=6 ?

The solutions to the equation 8p^2+56p+54=6 are p=-1,p=-6

Find the zeros of 8p^2+56p+54=6

The zeros of 8p^2+56p+54=6 are p=-1,p=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 p^{2} + 56 p + 54 = 6

p = - 1, p = - 6

Solution steps

8 p^{2} + 56 p + 54 = 6

Move

6

to the left side

8 p^{2} + 56 p + 48 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 56 \pm 5 6 ^{2} - 4 \cdot 8 \cdot 48}{2 \cdot 8}

5 6^{2} - 4 \cdot 8 \cdot 48 = 40

p_{1, 2} = \frac{- 56 \pm 40}{2 \cdot 8}

Separate the solutions

p_{1} = \frac{- 56 + 40}{2 \cdot 8}, p_{2} = \frac{- 56 - 40}{2 \cdot 8}

p = \frac{- 56 + 40}{2 \cdot 8} : - 1

p = \frac{- 56 - 40}{2 \cdot 8} : - 6

The solutions to the quadratic equation are:

p = - 1, p = - 6

15 x^{2} - 60 x = 0

x^{2} + 4 x - 30 = - 3 x - 3 x

9 x^{2} - 18 x = - 2

x^{2} + 6 = 27 x

x^{2} = (3 a)^{2} + (a 3)^{2}

What are the solutions to the equation 8p^2+56p+54=6 ?
The solutions to the equation 8p^2+56p+54=6 are p=-1,p=-6
Find the zeros of 8p^2+56p+54=6
The zeros of 8p^2+56p+54=6 are p=-1,p=-6