What are the solutions to the equation r^2-(3r)/5+2/25 =0 ?

The solutions to the equation r^2-(3r)/5+2/25 =0 are r= 2/5 ,r= 1/5

Find the zeros of r^2-(3r)/5+2/25 =0

The zeros of r^2-(3r)/5+2/25 =0 are r= 2/5 ,r= 1/5

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r^{2} - \frac{3 r}{5} + \frac{2}{25} = 0

r = \frac{2}{5}, r = \frac{1}{5}

Decimal Notation

r = 0.4, r = 0.2

Solution steps

r^{2} - \frac{3 r}{5} + \frac{2}{25} = 0

Find Least Common Multiplier of

5, 25 : 25

Multiply by LCM=

25

r^{2} \cdot 25 - \frac{3 r}{5} \cdot 25 + \frac{2}{25} \cdot 25 = 0 \cdot 25

Simplify

25 r^{2} - 15 r + 2 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 25 \cdot 2}{2 \cdot 25}

(- 15)^{2} - 4 \cdot 25 \cdot 2 = 5

r_{1, 2} = \frac{- ( - 15 ) \pm 5}{2 \cdot 25}

Separate the solutions

r_{1} = \frac{- ( - 15 ) + 5}{2 \cdot 25}, r_{2} = \frac{- ( - 15 ) - 5}{2 \cdot 25}

r = \frac{- ( - 15 ) + 5}{2 \cdot 25} : \frac{2}{5}

r = \frac{- ( - 15 ) - 5}{2 \cdot 25} : \frac{1}{5}

The solutions to the quadratic equation are:

r = \frac{2}{5}, r = \frac{1}{5}

y, x^{2} y^{2} - y^{2} = x^{2}

- 4 - 3 y^{2} = - 10

5 t^{2} - 11 = 0

r^{2} + \frac{3}{3} r + \frac{7}{3} = 0

3 v^{2} + 27 v = 0

What are the solutions to the equation r^2-(3r)/5+2/25 =0 ?
The solutions to the equation r^2-(3r)/5+2/25 =0 are r= 2/5 ,r= 1/5
Find the zeros of r^2-(3r)/5+2/25 =0
The zeros of r^2-(3r)/5+2/25 =0 are r= 2/5 ,r= 1/5