What are the solutions to the equation 3v^2+27v=0 ?

The solutions to the equation 3v^2+27v=0 are v=0,v=-9

Find the zeros of 3v^2+27v=0

The zeros of 3v^2+27v=0 are v=0,v=-9

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3 v^{2} + 27 v = 0

v = 0, v = - 9

Solution steps

3 v^{2} + 27 v = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 27 \pm 2 7 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

2 7^{2} - 4 \cdot 3 \cdot 0 = 27

v_{1, 2} = \frac{- 27 \pm 27}{2 \cdot 3}

Separate the solutions

v_{1} = \frac{- 27 + 27}{2 \cdot 3}, v_{2} = \frac{- 27 - 27}{2 \cdot 3}

v = \frac{- 27 + 27}{2 \cdot 3} : 0

v = \frac{- 27 - 27}{2 \cdot 3} : - 9

The solutions to the quadratic equation are:

v = 0, v = - 9

x^{2} + 10 x + 25 = - 9

x^{2} = 1 3^{2} + 1 2^{2}

49 x^{2} - 35 x + 25 = 0

x^{2} + 6 x + 3 = - 2

- 5 x^{2} - 7 x + 6 = 0

What are the solutions to the equation 3v^2+27v=0 ?
The solutions to the equation 3v^2+27v=0 are v=0,v=-9
Find the zeros of 3v^2+27v=0
The zeros of 3v^2+27v=0 are v=0,v=-9