What are the solutions to the equation x^2=13^2+12^2 ?

The solutions to the equation x^2=13^2+12^2 are x=sqrt(313),x=-sqrt(313)

Find the zeros of x^2=13^2+12^2

The zeros of x^2=13^2+12^2 are x=sqrt(313),x=-sqrt(313)

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x^{2} = 1 3^{2} + 1 2^{2}

x = 313, x = - 313

Decimal Notation

x = 17.69180 \dots, x = - 17.69180 \dots

Solution steps

x^{2} = 1 3^{2} + 1 2^{2}

Simplify

1 3^{2} + 1 2^{2} : 313

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 313, x = - 313

49 x^{2} - 35 x + 25 = 0

x^{2} + 6 x + 3 = - 2

- 5 x^{2} - 7 x + 6 = 0

\frac{1}{12} y^{2} = - y - 3

3 x^{2} - 20 x = 0

What are the solutions to the equation x^2=13^2+12^2 ?
The solutions to the equation x^2=13^2+12^2 are x=sqrt(313),x=-sqrt(313)
Find the zeros of x^2=13^2+12^2
The zeros of x^2=13^2+12^2 are x=sqrt(313),x=-sqrt(313)