What are the solutions to the equation -2(x+3)^2+8=0 ?

The solutions to the equation -2(x+3)^2+8=0 are x=-1,x=-5

Find the zeros of -2(x+3)^2+8=0

The zeros of -2(x+3)^2+8=0 are x=-1,x=-5

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- 2 (x + 3)^{2} + 8 = 0

x = - 1, x = - 5

Solution steps

- 2 (x + 3)^{2} + 8 = 0

Move

8

to the right side

- 2 (x + 3)^{2} = - 8

Divide both sides by

- 2

(x + 3)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 4 : x = - 1

Solve

x + 3 = - 4 : x = - 5

The solutions to the quadratic equation are:

x = - 1, x = - 5

x^{2} - 9 x + 8 = 0

- 5 x^{2} - 7 x + 5 = 0

x^{2} + 10 x + 25 = 24

\frac{5 \cdot x}{8} + \frac{x ^{2}}{51}

2 x^{2} - 25 x + 50 = 0

What are the solutions to the equation -2(x+3)^2+8=0 ?
The solutions to the equation -2(x+3)^2+8=0 are x=-1,x=-5
Find the zeros of -2(x+3)^2+8=0
The zeros of -2(x+3)^2+8=0 are x=-1,x=-5