What are the solutions to the equation a^2=-1,0y(a)a^{10}=24 ?

The solutions to the equation a^2=-1,0y(a)a^{10}=24 are a=i,a=-i

Find the zeros of a^2=-1,0y(a)a^{10}=24

The zeros of a^2=-1,0y(a)a^{10}=24 are a=i,a=-i

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a^{2} = - 1, 0 y (a) a^{10} = 24

a = i, a = - i

Solution steps

a^{2} = - 1, 0 \cdot y (a) a^{10} = 24

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = - 1, a = - - 1

- 1 = i

- - 1 = - i

a = i, a = - i

0 = 3 x^{2} - 10 x + 4

3 x^{2} - 36 = 3 x

x, (x + 2)^{2} + (y + 1)^{2} = 0

(z - 4)^{2} = (3 - z) (1 + 2 z)

y^{2} + 4 = 6 y - 4

What are the solutions to the equation a^2=-1,0y(a)a^{10}=24 ?
The solutions to the equation a^2=-1,0y(a)a^{10}=24 are a=i,a=-i
Find the zeros of a^2=-1,0y(a)a^{10}=24
The zeros of a^2=-1,0y(a)a^{10}=24 are a=i,a=-i