What are the solutions to the equation 2x^2+6x+17=0 ?

The solutions to the equation 2x^2+6x+17=0 are x=-3/2+i 5/2 ,x=-3/2-i 5/2

Find the zeros of 2x^2+6x+17=0

The zeros of 2x^2+6x+17=0 are x=-3/2+i 5/2 ,x=-3/2-i 5/2

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2 x^{2} + 6 x + 17 = 0

x = - \frac{3}{2} + i \frac{5}{2}, x = - \frac{3}{2} - i \frac{5}{2}

Solution steps

2 x^{2} + 6 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 \cdot 17}{2 \cdot 2}

Simplify

6^{2} - 4 \cdot 2 \cdot 17 : 10 i

x_{1, 2} = \frac{- 6 \pm 10 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 10 i}{2 \cdot 2}, x_{2} = \frac{- 6 - 10 i}{2 \cdot 2}

x = \frac{- 6 + 10 i}{2 \cdot 2} : - \frac{3}{2} + i \frac{5}{2}

x = \frac{- 6 - 10 i}{2 \cdot 2} : - \frac{3}{2} - i \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{5}{2}, x = - \frac{3}{2} - i \frac{5}{2}

4 x^{2} - 56 x + 180 = 0

9^{2} + 1 0^{2} = x^{2}

x^{2} - 8 = 92

- \frac{1}{10} x^{2} + 1 = 0

0 = x^{2} + 6 x - 27

What are the solutions to the equation 2x^2+6x+17=0 ?
The solutions to the equation 2x^2+6x+17=0 are x=-3/2+i 5/2 ,x=-3/2-i 5/2
Find the zeros of 2x^2+6x+17=0
The zeros of 2x^2+6x+17=0 are x=-3/2+i 5/2 ,x=-3/2-i 5/2