What are the solutions to the equation 0=x^2+6x-27 ?

The solutions to the equation 0=x^2+6x-27 are x=3,x=-9

Find the zeros of 0=x^2+6x-27

The zeros of 0=x^2+6x-27 are x=3,x=-9

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0 = x^{2} + 6 x - 27

x = 3, x = - 9

Solution steps

0 = x^{2} + 6 x - 27

Switch sides

x^{2} + 6 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 27 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 27) = 12

x_{1, 2} = \frac{- 6 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 12}{2 \cdot 1}, x_{2} = \frac{- 6 - 12}{2 \cdot 1}

x = \frac{- 6 + 12}{2 \cdot 1} : 3

x = \frac{- 6 - 12}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 3, x = - 9

- 2 x^{2} + 4 x - 5

- 1 - x^{2} = 0

x, z = x^{2} + 2 x y

4 x^{2} + 6 x - 2 = 0

s^{2} - 6 s + 11

What are the solutions to the equation 0=x^2+6x-27 ?
The solutions to the equation 0=x^2+6x-27 are x=3,x=-9
Find the zeros of 0=x^2+6x-27
The zeros of 0=x^2+6x-27 are x=3,x=-9