What are the solutions to the equation 4x^2+6x-2=0 ?

The solutions to the equation 4x^2+6x-2=0 are x=(-3+sqrt(17))/4 ,x=-(3+sqrt(17))/4

Find the zeros of 4x^2+6x-2=0

The zeros of 4x^2+6x-2=0 are x=(-3+sqrt(17))/4 ,x=-(3+sqrt(17))/4

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4 x^{2} + 6 x - 2 = 0

x = \frac{- 3 + 17}{4}, x = - \frac{3 + 17}{4}

Decimal Notation

x = 0.28077 \dots, x = - 1.78077 \dots

Solution steps

4 x^{2} + 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

6^{2} - 4 \cdot 4 (- 2) = 217

x_{1, 2} = \frac{- 6 \pm 2 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 6 + 2 17}{2 \cdot 4}, x_{2} = \frac{- 6 - 2 17}{2 \cdot 4}

x = \frac{- 6 + 2 17}{2 \cdot 4} : \frac{- 3 + 17}{4}

x = \frac{- 6 - 2 17}{2 \cdot 4} : - \frac{3 + 17}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 17}{4}, x = - \frac{3 + 17}{4}

s^{2} - 6 s + 11

s^{2} - 6 s + 13

x^{2} = 3 9^{2} + 16 0^{2}

- 0.3 x^{2} + 0.6 x = 22

x + 3 = 9 - x^{2}

What are the solutions to the equation 4x^2+6x-2=0 ?
The solutions to the equation 4x^2+6x-2=0 are x=(-3+sqrt(17))/4 ,x=-(3+sqrt(17))/4
Find the zeros of 4x^2+6x-2=0
The zeros of 4x^2+6x-2=0 are x=(-3+sqrt(17))/4 ,x=-(3+sqrt(17))/4