What are the solutions to the equation x^2=39^2+160^2 ?

The solutions to the equation x^2=39^2+160^2 are x=sqrt(27121),x=-sqrt(27121)

Find the zeros of x^2=39^2+160^2

The zeros of x^2=39^2+160^2 are x=sqrt(27121),x=-sqrt(27121)

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x^{2} = 3 9^{2} + 16 0^{2}

x = 27121, x = - 27121

Decimal Notation

x = 164.68454 \dots, x = - 164.68454 \dots

Solution steps

x^{2} = 3 9^{2} + 16 0^{2}

Simplify

3 9^{2} + 16 0^{2} : 27121

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 27121, x = - 27121

- 0.3 x^{2} + 0.6 x = 22

x + 3 = 9 - x^{2}

2 x^{2} + 3 - 1 = 0

- 4 b^{2} - 3 b + 14 = 4

x^{2} - 2.4 x = 2.2

What are the solutions to the equation x^2=39^2+160^2 ?
The solutions to the equation x^2=39^2+160^2 are x=sqrt(27121),x=-sqrt(27121)
Find the zeros of x^2=39^2+160^2
The zeros of x^2=39^2+160^2 are x=sqrt(27121),x=-sqrt(27121)