What are the solutions to the equation 10^2+b^2=20^2 ?

The solutions to the equation 10^2+b^2=20^2 are b=10sqrt(3),b=-10sqrt(3)

Find the zeros of 10^2+b^2=20^2

The zeros of 10^2+b^2=20^2 are b=10sqrt(3),b=-10sqrt(3)

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1 0^{2} + b^{2} = 2 0^{2}

b = 103, b = - 103

Decimal Notation

b = 17.32050 \dots, b = - 17.32050 \dots

Solution steps

1 0^{2} + b^{2} = 2 0^{2}

Move

1 0^{2}

to the right side

b^{2} = 300

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 300, b = - 300

300 = 103

- 300 = - 103

b = 103, b = - 103

36 u = 9 u^{2}

3 x^{2} = 5 x - 3

- x^{2} - 12 = 0

4^{2} + 1 2^{2} = x^{2}

64 x^{2} - 80 x

What are the solutions to the equation 10^2+b^2=20^2 ?
The solutions to the equation 10^2+b^2=20^2 are b=10sqrt(3),b=-10sqrt(3)
Find the zeros of 10^2+b^2=20^2
The zeros of 10^2+b^2=20^2 are b=10sqrt(3),b=-10sqrt(3)