What are the solutions to the equation -x^2-12=0 ?

The solutions to the equation -x^2-12=0 are x=2sqrt(3)i,x=-2sqrt(3)i

Find the zeros of -x^2-12=0

The zeros of -x^2-12=0 are x=2sqrt(3)i,x=-2sqrt(3)i

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- x^{2} - 12 = 0

x = 23 i, x = - 23 i

Solution steps

- x^{2} - 12 = 0

Move

12

to the right side

- x^{2} = 12

Divide both sides by

- 1

x^{2} = - 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 12, x = - - 12

- 12 = 23 i

- - 12 = - 23 i

x = 23 i, x = - 23 i

4^{2} + 1 2^{2} = x^{2}

64 x^{2} - 80 x

4 = 3 x^{2} - 26 x + 44

x^{2} + 20 x + 28 = 0

4 y^{2} = 8 y + 5

What are the solutions to the equation -x^2-12=0 ?
The solutions to the equation -x^2-12=0 are x=2sqrt(3)i,x=-2sqrt(3)i
Find the zeros of -x^2-12=0
The zeros of -x^2-12=0 are x=2sqrt(3)i,x=-2sqrt(3)i