What are the solutions to the equation completesquare x^2+20x+28=0 ?

The solutions to the equation completesquare x^2+20x+28=0 are x=6sqrt(2)-10,x=-6sqrt(2)-10

Find the zeros of completesquare x^2+20x+28=0

The zeros of completesquare x^2+20x+28=0 are x=6sqrt(2)-10,x=-6sqrt(2)-10

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x^{2} + 20 x + 28 = 0

x = 62 - 10, x = - 62 - 10

Decimal Notation

x = - 1.51471 \dots, x = - 18.48528 \dots

Solution steps

x^{2} + 20 x + 28 = 0

Move

28

to the right side

x^{2} + 20 x = - 28

Rewrite in the form

(x + a)^{2} = b

(x + 10)^{2} = 72

For

the solutions are

f (x) = a, - a

Solve

x + 10 = 72 : x = 62 - 10

Solve

x + 10 = - 72 : x = - 62 - 10

The solutions to the quadratic equation are:

x = 62 - 10, x = - 62 - 10

4 y^{2} = 8 y + 5

- 2 x^{2} + 2 x + 9 = - 5 x

p, \frac{3 p ^{2} - x}{y} = \frac{- x + 17}{- 4}

x^{2} + (7 - x)^{2} = 49

- 3 (x + 2)^{2} = 12

What are the solutions to the equation completesquare x^2+20x+28=0 ?
The solutions to the equation completesquare x^2+20x+28=0 are x=6sqrt(2)-10,x=-6sqrt(2)-10
Find the zeros of completesquare x^2+20x+28=0
The zeros of completesquare x^2+20x+28=0 are x=6sqrt(2)-10,x=-6sqrt(2)-10