What are the solutions to the equation -3(x+2)^2=12 ?

The solutions to the equation -3(x+2)^2=12 are x=2i-2,x=-2i-2

Find the zeros of -3(x+2)^2=12

The zeros of -3(x+2)^2=12 are x=2i-2,x=-2i-2

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- 3 (x + 2)^{2} = 12

x = 2 i - 2, x = - 2 i - 2

Solution steps

- 3 (x + 2)^{2} = 12

Divide both sides by

- 3

(x + 2)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = - 4 : x = 2 i - 2

Solve

x + 2 = - - 4 : x = - 2 i - 2

The solutions to the quadratic equation are:

x = 2 i - 2, x = - 2 i - 2

x^{2} = 7 x + 12

x^{2} + 5 x = - 6

r, x^{2} - y^{2} = r^{2}

x^{2} - 15 x = - 26

x, x^{2} + 2 y^{2} + 3 z^{2} = 1

What are the solutions to the equation -3(x+2)^2=12 ?
The solutions to the equation -3(x+2)^2=12 are x=2i-2,x=-2i-2
Find the zeros of -3(x+2)^2=12
The zeros of -3(x+2)^2=12 are x=2i-2,x=-2i-2