What are the solutions to the equation x^2-15x=-26 ?

The solutions to the equation x^2-15x=-26 are x=13,x=2

Find the zeros of x^2-15x=-26

The zeros of x^2-15x=-26 are x=13,x=2

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x^{2} - 15 x = - 26

x = 13, x = 2

Solution steps

x^{2} - 15 x = - 26

Move

26

to the left side

x^{2} - 15 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 26}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 26 = 11

x_{1, 2} = \frac{- ( - 15 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 11}{2 \cdot 1}

x = \frac{- ( - 15 ) + 11}{2 \cdot 1} : 13

x = \frac{- ( - 15 ) - 11}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 13, x = 2

x, x^{2} + 2 y^{2} + 3 z^{2} = 1

x^{2} - 96 = 0

12 + 24 x^{2} - 34 x = 0

\frac{x ^{2} - x}{9} = 8

m^{2} - 2 m - 63 = 0

What are the solutions to the equation x^2-15x=-26 ?
The solutions to the equation x^2-15x=-26 are x=13,x=2
Find the zeros of x^2-15x=-26
The zeros of x^2-15x=-26 are x=13,x=2