What are the solutions to the equation (x^2-x)/9 =8 ?

The solutions to the equation (x^2-x)/9 =8 are x=9,x=-8

Find the zeros of (x^2-x)/9 =8

The zeros of (x^2-x)/9 =8 are x=9,x=-8

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\frac{x ^{2} - x}{9} = 8

x = 9, x = - 8

Solution steps

\frac{x ^{2} - x}{9} = 8

Multiply both sides by

9

x^{2} - x = 72

Move

72

to the left side

x^{2} - x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 72) = 17

x_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 1}

x = \frac{- ( - 1 ) + 17}{2 \cdot 1} : 9

x = \frac{- ( - 1 ) - 17}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 9, x = - 8

m^{2} - 2 m - 63 = 0

4 x^{2} + 48 x - 81 = 0

1^{2} = m^{2} + (- \frac{3}{2})^{2}

\frac{( x - 3 ) ^{2}}{25} + \frac{( 7 - 4 ) ^{2}}{169} = 0

s^{2} + 2 s - 2 = 0

What are the solutions to the equation (x^2-x)/9 =8 ?
The solutions to the equation (x^2-x)/9 =8 are x=9,x=-8
Find the zeros of (x^2-x)/9 =8
The zeros of (x^2-x)/9 =8 are x=9,x=-8