What are the solutions to the equation ((x-3)^2)/(25)+((7-4)^2)/(169)=0 ?

The solutions to the equation ((x-3)^2)/(25)+((7-4)^2)/(169)=0 are x=3+i 15/13 ,x=3-i 15/13

Find the zeros of ((x-3)^2)/(25)+((7-4)^2)/(169)=0

The zeros of ((x-3)^2)/(25)+((7-4)^2)/(169)=0 are x=3+i 15/13 ,x=3-i 15/13

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\frac{( x - 3 ) ^{2}}{25} + \frac{( 7 - 4 ) ^{2}}{169} = 0

x = 3 + i \frac{15}{13}, x = 3 - i \frac{15}{13}

Solution steps

\frac{( x - 3 ) ^{2}}{25} + \frac{( 7 - 4 ) ^{2}}{169} = 0

Move

\frac{( 7 - 4 ) ^{2}}{169}

to the right side

\frac{( x - 3 ) ^{2}}{25} = - \frac{9}{169}

Multiply both sides by

25

(x - 3)^{2} = - \frac{225}{169}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = - \frac{225}{169} : x = 3 + i \frac{15}{13}

Solve

x - 3 = - - \frac{225}{169} : x = 3 - i \frac{15}{13}

The solutions to the quadratic equation are:

x = 3 + i \frac{15}{13}, x = 3 - i \frac{15}{13}

s^{2} + 2 s - 2 = 0

0 = x^{2} + 6 x

x^{2} + x - 4 = 0

5 x^{2} - 2 x - 39 = 0

- 3 (x + 5)^{2} - 4 = 77

What are the solutions to the equation ((x-3)^2)/(25)+((7-4)^2)/(169)=0 ?
The solutions to the equation ((x-3)^2)/(25)+((7-4)^2)/(169)=0 are x=3+i 15/13 ,x=3-i 15/13
Find the zeros of ((x-3)^2)/(25)+((7-4)^2)/(169)=0
The zeros of ((x-3)^2)/(25)+((7-4)^2)/(169)=0 are x=3+i 15/13 ,x=3-i 15/13