What are the solutions to the equation 7x^2-2x=5 ?

The solutions to the equation 7x^2-2x=5 are x=1,x=-5/7

Find the zeros of 7x^2-2x=5

The zeros of 7x^2-2x=5 are x=1,x=-5/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 x^{2} - 2 x = 5

x = 1, x = - \frac{5}{7}

Decimal Notation

x = 1, x = - 0.71428 \dots

Solution steps

7 x^{2} - 2 x = 5

Move

5

to the left side

7 x^{2} - 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 7 ( - 5 )}{2 \cdot 7}

(- 2)^{2} - 4 \cdot 7 (- 5) = 12

x_{1, 2} = \frac{- ( - 2 ) \pm 12}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 12}{2 \cdot 7}, x_{2} = \frac{- ( - 2 ) - 12}{2 \cdot 7}

x = \frac{- ( - 2 ) + 12}{2 \cdot 7} : 1

x = \frac{- ( - 2 ) - 12}{2 \cdot 7} : - \frac{5}{7}

The solutions to the quadratic equation are:

x = 1, x = - \frac{5}{7}

7 x^{2} - 2 x = 2

3 x^{2} = 2 (x - 1)^{2} + 3

x^{(2)} + 20 x + 28 = 9

6 - 5 x + x^{2} = 0

3 x^{2} - 4 x + 2 = 2 - 2 x

What are the solutions to the equation 7x^2-2x=5 ?
The solutions to the equation 7x^2-2x=5 are x=1,x=-5/7
Find the zeros of 7x^2-2x=5
The zeros of 7x^2-2x=5 are x=1,x=-5/7