What are the solutions to the equation 3x^2-4x+2=2-2x ?

The solutions to the equation 3x^2-4x+2=2-2x are x= 2/3 ,x=0

Find the zeros of 3x^2-4x+2=2-2x

The zeros of 3x^2-4x+2=2-2x are x= 2/3 ,x=0

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3 x^{2} - 4 x + 2 = 2 - 2 x

x = \frac{2}{3}, x = 0

Decimal Notation

x = 0.66666 \dots, x = 0

Solution steps

3 x^{2} - 4 x + 2 = 2 - 2 x

Move

2 x

to the left side

3 x^{2} - 2 x + 2 = 2

Move

2

to the left side

3 x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2}{2 \cdot 3} : \frac{2}{3}

x = \frac{- ( - 2 ) - 2}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = 0

2 t^{2} + 4 t + 2 = 0

x^{2} - 2 x - 22 = 2 x - 1

lo g_{10} (9) = x^{2} + 3

x, x^{2} + 3 y^{2} + 2 x y = 0

a, a^{2} + 3 a d - d^{2} = 0

What are the solutions to the equation 3x^2-4x+2=2-2x ?
The solutions to the equation 3x^2-4x+2=2-2x are x= 2/3 ,x=0
Find the zeros of 3x^2-4x+2=2-2x
The zeros of 3x^2-4x+2=2-2x are x= 2/3 ,x=0