What are the solutions to the equation x^2-2x-22=2x-1 ?

The solutions to the equation x^2-2x-22=2x-1 are x=7,x=-3

Find the zeros of x^2-2x-22=2x-1

The zeros of x^2-2x-22=2x-1 are x=7,x=-3

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x^{2} - 2 x - 22 = 2 x - 1

x = 7, x = - 3

Solution steps

x^{2} - 2 x - 22 = 2 x - 1

Move

1

to the left side

x^{2} - 2 x - 21 = 2 x

Move

2 x

to the left side

x^{2} - 4 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 21) = 10

x_{1, 2} = \frac{- ( - 4 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 10}{2 \cdot 1}

x = \frac{- ( - 4 ) + 10}{2 \cdot 1} : 7

x = \frac{- ( - 4 ) - 10}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 7, x = - 3

lo g_{10} (9) = x^{2} + 3

x, x^{2} + 3 y^{2} + 2 x y = 0

a, a^{2} + 3 a d - d^{2} = 0

2 + 5 r - 10 r^{2} = 0

x^{2} = 4 x + 2

What are the solutions to the equation x^2-2x-22=2x-1 ?
The solutions to the equation x^2-2x-22=2x-1 are x=7,x=-3
Find the zeros of x^2-2x-22=2x-1
The zeros of x^2-2x-22=2x-1 are x=7,x=-3