What are the solutions to the equation solvefor x,x^2+3y^2+2xy=0 ?

The solutions to the equation solvefor x,x^2+3y^2+2xy=0 are x=-y+sqrt(2)iy,x=-y-sqrt(2)iy

Find the zeros of solvefor x,x^2+3y^2+2xy=0

The zeros of solvefor x,x^2+3y^2+2xy=0 are x=-y+sqrt(2)iy,x=-y-sqrt(2)iy

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solve for

x, x^{2} + 3 y^{2} + 2 x y = 0

x = - y + 2 i y, x = - y - 2 i y

Solution steps

x^{2} + 3 y^{2} + 2 x y = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 y x + 3 y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 y \pm ( 2 y ) ^{2} - 4 \cdot 1 \cdot 3 y ^{2}}{2 \cdot 1}

Simplify

(2 y)^{2} - 4 \cdot 1 \cdot 3 y^{2} : 22 i y

x_{1, 2} = \frac{- 2 y \pm 2 2 i y}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 y + 2 2 i y}{2 \cdot 1}, x_{2} = \frac{- 2 y - 2 2 i y}{2 \cdot 1}

x = \frac{- 2 y + 2 2 i y}{2 \cdot 1} : - y + 2 i y

x = \frac{- 2 y - 2 2 i y}{2 \cdot 1} : - y - 2 i y

The solutions to the quadratic equation are:

x = - y + 2 i y, x = - y - 2 i y

a, a^{2} + 3 a d - d^{2} = 0

2 + 5 r - 10 r^{2} = 0

x^{2} = 4 x + 2

(3 x + 1)^{2} = 16

3 x^{2} + 10 x = - 3

What are the solutions to the equation solvefor x,x^2+3y^2+2xy=0 ?
The solutions to the equation solvefor x,x^2+3y^2+2xy=0 are x=-y+sqrt(2)iy,x=-y-sqrt(2)iy
Find the zeros of solvefor x,x^2+3y^2+2xy=0
The zeros of solvefor x,x^2+3y^2+2xy=0 are x=-y+sqrt(2)iy,x=-y-sqrt(2)iy