What are the solutions to the equation (3x+1)^2=16 ?

The solutions to the equation (3x+1)^2=16 are x=1,x=-5/3

Find the zeros of (3x+1)^2=16

The zeros of (3x+1)^2=16 are x=1,x=-5/3

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(3 x + 1)^{2} = 16

x = 1, x = - \frac{5}{3}

Decimal Notation

x = 1, x = - 1.66666 \dots

Solution steps

(3 x + 1)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 1 = 16 : x = 1

Solve

3 x + 1 = - 16 : x = - \frac{5}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{5}{3}

3 x^{2} + 10 x = - 3

- \frac{42}{5} x + 474 = \frac{62}{100} (x - 59)^{2}

5 x (x - 1) - 4 x (x + 1) = - 2 (9 x + 4)

- 5 x^{2} + 30 x = 0

x^{2} + 3 x = 36

What are the solutions to the equation (3x+1)^2=16 ?
The solutions to the equation (3x+1)^2=16 are x=1,x=-5/3
Find the zeros of (3x+1)^2=16
The zeros of (3x+1)^2=16 are x=1,x=-5/3