What are the solutions to the equation 5x(x-1)-4x(x+1)=-2(9x+4) ?

The solutions to the equation 5x(x-1)-4x(x+1)=-2(9x+4) are x=-1,x=-8

Find the zeros of 5x(x-1)-4x(x+1)=-2(9x+4)

The zeros of 5x(x-1)-4x(x+1)=-2(9x+4) are x=-1,x=-8

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5 x (x - 1) - 4 x (x + 1) = - 2 (9 x + 4)

x = - 1, x = - 8

Solution steps

5 x (x - 1) - 4 x (x + 1) = - 2 (9 x + 4)

Expand

5 x (x - 1) - 4 x (x + 1) : x^{2} - 9 x

Expand

- 2 (9 x + 4) : - 18 x - 8

x^{2} - 9 x = - 18 x - 8

Move

8

to the left side

x^{2} - 9 x + 8 = - 18 x

Move

18 x

to the left side

x^{2} + 9 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 8 = 7

x_{1, 2} = \frac{- 9 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 7}{2 \cdot 1}, x_{2} = \frac{- 9 - 7}{2 \cdot 1}

x = \frac{- 9 + 7}{2 \cdot 1} : - 1

x = \frac{- 9 - 7}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 1, x = - 8

- 5 x^{2} + 30 x = 0

x^{2} + 3 x = 36

x^{2} + 3 x = 12

x^{2} + 3 x = - 3

5 x^{2} + 7 x = - 1

What are the solutions to the equation 5x(x-1)-4x(x+1)=-2(9x+4) ?
The solutions to the equation 5x(x-1)-4x(x+1)=-2(9x+4) are x=-1,x=-8
Find the zeros of 5x(x-1)-4x(x+1)=-2(9x+4)
The zeros of 5x(x-1)-4x(x+1)=-2(9x+4) are x=-1,x=-8