What is (((4-x)))/2-((2x-1))/3 <x-2 ?

The solution to (((4-x)))/2-((2x-1))/3 2

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(((4-x)))/2-((2x-1))/3 <x-2

\frac{( ( 4 - x ) )}{2} - \frac{( 2 x - 1 )}{3} < x - 2

x > 2

Interval Notation

(2, \infty)

Solution steps

\frac{( ( 4 - x ) )}{2} - \frac{( 2 x - 1 )}{3} < x - 2

\frac{4 - x}{2} - \frac{2 x - 1}{3} < x - 2

Multiply by LCM

3 (- x + 4) - 2 (2 x - 1) < 6 x - 12

Expand

3 (- x + 4) - 2 (2 x - 1) : - 7 x + 14

- 7 x + 14 < 6 x - 12

Move

14

to the right side

- 7 x < 6 x - 26

Move

6 x

to the left side

- 13 x < - 26

Multiply both sides by

- 1

13 x > 26

Divide both sides by

13

x > 2

\frac{2 ^{- 2} m ^{- 3}}{n ^{0}}

(2 x^{3} y^{- \frac{1}{4}})^{2} (8 y^{- \frac{3}{2}})^{- \frac{1}{3}}

10 v - 80 \geq 5 (4 - 2 v)

\frac{b ^{7}}{b ^{6}}

∣ x - 3 ∣ < 3 x - 4

What is (((4-x)))/2-((2x-1))/3 <x-2 ?
The solution to (((4-x)))/2-((2x-1))/3 <x-2 is x>2