What are the solutions to the equation -2x^2-4x=-30 ?

The solutions to the equation -2x^2-4x=-30 are x=-5,x=3

Find the zeros of -2x^2-4x=-30

The zeros of -2x^2-4x=-30 are x=-5,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} - 4 x = - 30

x = - 5, x = 3

Solution steps

- 2 x^{2} - 4 x = - 30

Move

30

to the left side

- 2 x^{2} - 4 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) \cdot 30}{2 ( - 2 )}

(- 4)^{2} - 4 (- 2) \cdot 30 = 16

x_{1, 2} = \frac{- ( - 4 ) \pm 16}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 16}{2 ( - 2 )}, x_{2} = \frac{- ( - 4 ) - 16}{2 ( - 2 )}

x = \frac{- ( - 4 ) + 16}{2 ( - 2 )} : - 5

x = \frac{- ( - 4 ) - 16}{2 ( - 2 )} : 3

The solutions to the quadratic equation are:

x = - 5, x = 3

9 p^{2} + 6 p + 1 = 0

4 x^{2} + 3 x + 9 = 0

6 x^{2} + 8 x - 6 = 0

x^{2} + 16 x + (64) = 9 + (64)

- 3 λ + λ^{2} + 2 = 0

What are the solutions to the equation -2x^2-4x=-30 ?
The solutions to the equation -2x^2-4x=-30 are x=-5,x=3
Find the zeros of -2x^2-4x=-30
The zeros of -2x^2-4x=-30 are x=-5,x=3