What are the solutions to the equation 6x^2+8x-6=0 ?

The solutions to the equation 6x^2+8x-6=0 are x=(-2+sqrt(13))/3 ,x=-(2+sqrt(13))/3

Find the zeros of 6x^2+8x-6=0

The zeros of 6x^2+8x-6=0 are x=(-2+sqrt(13))/3 ,x=-(2+sqrt(13))/3

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6 x^{2} + 8 x - 6 = 0

x = \frac{- 2 + 13}{3}, x = - \frac{2 + 13}{3}

Decimal Notation

x = 0.53518 \dots, x = - 1.86851 \dots

Solution steps

6 x^{2} + 8 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 6 ( - 6 )}{2 \cdot 6}

8^{2} - 4 \cdot 6 (- 6) = 413

x_{1, 2} = \frac{- 8 \pm 4 13}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 8 + 4 13}{2 \cdot 6}, x_{2} = \frac{- 8 - 4 13}{2 \cdot 6}

x = \frac{- 8 + 4 13}{2 \cdot 6} : \frac{- 2 + 13}{3}

x = \frac{- 8 - 4 13}{2 \cdot 6} : - \frac{2 + 13}{3}

The solutions to the quadratic equation are:

x = \frac{- 2 + 13}{3}, x = - \frac{2 + 13}{3}

x^{2} + 16 x + (64) = 9 + (64)

- 3 λ + λ^{2} + 2 = 0

3 n^{2} - 75 = 0

u^{2} + 18 u

(1 - 3) x^{2} - (3 + 1) x - 2 = 0

What are the solutions to the equation 6x^2+8x-6=0 ?
The solutions to the equation 6x^2+8x-6=0 are x=(-2+sqrt(13))/3 ,x=-(2+sqrt(13))/3
Find the zeros of 6x^2+8x-6=0
The zeros of 6x^2+8x-6=0 are x=(-2+sqrt(13))/3 ,x=-(2+sqrt(13))/3