What are the solutions to the equation 5x^2+9x+5=0 ?

The solutions to the equation 5x^2+9x+5=0 are x=-9/10+i(sqrt(19))/(10),x=-9/10-i(sqrt(19))/(10)

Find the zeros of 5x^2+9x+5=0

The zeros of 5x^2+9x+5=0 are x=-9/10+i(sqrt(19))/(10),x=-9/10-i(sqrt(19))/(10)

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5 x^{2} + 9 x + 5 = 0

x = - \frac{9}{10} + i \frac{19}{10}, x = - \frac{9}{10} - i \frac{19}{10}

Solution steps

5 x^{2} + 9 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

Simplify

9^{2} - 4 \cdot 5 \cdot 5 : 19 i

x_{1, 2} = \frac{- 9 \pm 19 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 9 + 19 i}{2 \cdot 5}, x_{2} = \frac{- 9 - 19 i}{2 \cdot 5}

x = \frac{- 9 + 19 i}{2 \cdot 5} : - \frac{9}{10} + i \frac{19}{10}

x = \frac{- 9 - 19 i}{2 \cdot 5} : - \frac{9}{10} - i \frac{19}{10}

The solutions to the quadratic equation are:

x = - \frac{9}{10} + i \frac{19}{10}, x = - \frac{9}{10} - i \frac{19}{10}

3 x (x + 1) - x = 33 - (x - 3)^{2}

x, z = x^{2} + 2 y^{2} + 6 x y - 6 x + 10 y + 5

x^{2} + \frac{4}{3} x + \frac{4}{9} = 0

4 a^{2} + 3 a - 22 = 0

10 x^{2} + 8 x - 9 = 0

What are the solutions to the equation 5x^2+9x+5=0 ?
The solutions to the equation 5x^2+9x+5=0 are x=-9/10+i(sqrt(19))/(10),x=-9/10-i(sqrt(19))/(10)
Find the zeros of 5x^2+9x+5=0
The zeros of 5x^2+9x+5=0 are x=-9/10+i(sqrt(19))/(10),x=-9/10-i(sqrt(19))/(10)