What are the solutions to the equation 8x^2+7=-149 ?

The solutions to the equation 8x^2+7=-149 are x=sqrt(39/2)i,x=-sqrt(39/2)i

Find the zeros of 8x^2+7=-149

The zeros of 8x^2+7=-149 are x=sqrt(39/2)i,x=-sqrt(39/2)i

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8 x^{2} + 7 = - 149

x = \frac{39}{2} i, x = - \frac{39}{2} i

Solution steps

8 x^{2} + 7 = - 149

Move

7

to the right side

8 x^{2} = - 156

Divide both sides by

8

x^{2} = - \frac{39}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{39}{2}, x = - - \frac{39}{2}

- \frac{39}{2} = \frac{39}{2} i

- - \frac{39}{2} = - \frac{39}{2} i

x = \frac{39}{2} i, x = - \frac{39}{2} i

6 x^{2} + 3 x + 6 = 414

3 x^{2} + 5 = 5 x^{2} - 8

220 + 11 x - 11 x^{2} = 11 x^{2} - 55 x

8 x^{2} + 4 x + 2 = 0

0 = 12 x^{2} - 24 x + 9

What are the solutions to the equation 8x^2+7=-149 ?
The solutions to the equation 8x^2+7=-149 are x=sqrt(39/2)i,x=-sqrt(39/2)i
Find the zeros of 8x^2+7=-149
The zeros of 8x^2+7=-149 are x=sqrt(39/2)i,x=-sqrt(39/2)i