What are the solutions to the equation x^2-8x=-6 ?

The solutions to the equation x^2-8x=-6 are x=4+sqrt(10),x=4-sqrt(10)

Find the zeros of x^2-8x=-6

The zeros of x^2-8x=-6 are x=4+sqrt(10),x=4-sqrt(10)

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x^{2} - 8 x = - 6

x = 4 + 10, x = 4 - 10

Decimal Notation

x = 7.16227 \dots, x = 0.83772 \dots

Solution steps

x^{2} - 8 x = - 6

Move

6

to the left side

x^{2} - 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 6 = 210

x_{1, 2} = \frac{- ( - 8 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 10}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 10}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 10}{2 \cdot 1} : 4 + 10

x = \frac{- ( - 8 ) - 2 10}{2 \cdot 1} : 4 - 10

The solutions to the quadratic equation are:

x = 4 + 10, x = 4 - 10

x^{2} - 8 x = - 4

x^{2} = 5 x - 9

x, x^{2} + y^{3} - 9 = 0

x, 3 x^{2} - 8 x y - 12 y^{2} - 30 x - 64 y = 0

5 x^{2} + 0 x - 13 = 0

What are the solutions to the equation x^2-8x=-6 ?
The solutions to the equation x^2-8x=-6 are x=4+sqrt(10),x=4-sqrt(10)
Find the zeros of x^2-8x=-6
The zeros of x^2-8x=-6 are x=4+sqrt(10),x=4-sqrt(10)