What are the solutions to the equation p^2-6p-72=0 ?

The solutions to the equation p^2-6p-72=0 are p=12,p=-6

Find the zeros of p^2-6p-72=0

The zeros of p^2-6p-72=0 are p=12,p=-6

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p^{2} - 6 p - 72 = 0

p = 12, p = - 6

Solution steps

p^{2} - 6 p - 72 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 72) = 18

p_{1, 2} = \frac{- ( - 6 ) \pm 18}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 6 ) + 18}{2 \cdot 1}, p_{2} = \frac{- ( - 6 ) - 18}{2 \cdot 1}

p = \frac{- ( - 6 ) + 18}{2 \cdot 1} : 12

p = \frac{- ( - 6 ) - 18}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

p = 12, p = - 6

x^{2} - 3 - 10 = 0

\frac{x ^{2}}{16} + \frac{x ^{2}}{12} = 1

- 2 x^{2} + 5 x - 2 = 1

0 = 2 (x + 3)^{2} - 8

4 y^{2} + 8 y

What are the solutions to the equation p^2-6p-72=0 ?
The solutions to the equation p^2-6p-72=0 are p=12,p=-6
Find the zeros of p^2-6p-72=0
The zeros of p^2-6p-72=0 are p=12,p=-6