What are the solutions to the equation completesquare 4y^2+8y ?

The solutions to the equation completesquare 4y^2+8y are 4(y+1)^2-4

Find the zeros of completesquare 4y^2+8y

The zeros of completesquare 4y^2+8y are 4(y+1)^2-4

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complete the square

4 y^{2} + 8 y

4 (y + 1)^{2} - 4

Solution steps

4 y^{2} + 8 y

Write

4 y^{2} + 8 y

in the form:

x^{2} + 2 a x + a^{2}

Factor out

4

4 (y^{2} + 2 y)

2 a = 2 : a = 1

Add and subtract

1^{2}

4 (y^{2} + 2 y + 1^{2} - 1^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

y^{2} + 2 y + 1^{2} = (y + 1)^{2}

4 ((y + 1)^{2} - 1^{2})

Simplify

4 (y + 1)^{2} - 4

12 x^{2} - 24 x - 40 = 0

25 - x^{2} = 9

x^{2} - 25

1.371 6^{2} = x^{2} + (\frac{1.3716}{2})^{2}

7 x^{2} - 5 = 23

What are the solutions to the equation completesquare 4y^2+8y ?
The solutions to the equation completesquare 4y^2+8y are 4(y+1)^2-4
Find the zeros of completesquare 4y^2+8y
The zeros of completesquare 4y^2+8y are 4(y+1)^2-4