What are the solutions to the equation -4x^2+4x+15=0 ?

The solutions to the equation -4x^2+4x+15=0 are x=-3/2 ,x= 5/2

Find the zeros of -4x^2+4x+15=0

The zeros of -4x^2+4x+15=0 are x=-3/2 ,x= 5/2

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- 4 x^{2} + 4 x + 15 = 0

x = - \frac{3}{2}, x = \frac{5}{2}

Decimal Notation

x = - 1.5, x = 2.5

Solution steps

- 4 x^{2} + 4 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 4 ) \cdot 15}{2 ( - 4 )}

4^{2} - 4 (- 4) \cdot 15 = 16

x_{1, 2} = \frac{- 4 \pm 16}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 4 + 16}{2 ( - 4 )}, x_{2} = \frac{- 4 - 16}{2 ( - 4 )}

x = \frac{- 4 + 16}{2 ( - 4 )} : - \frac{3}{2}

x = \frac{- 4 - 16}{2 ( - 4 )} : \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = \frac{5}{2}

2 x^{2} - 3 = 125

x^{2} - 2451 x - 2631 = 0

4 x^{2} - 9 x - 90 = 0

- 0.1 x^{2} + 80 = 0.3 x^{2} + x + 30

8 x^{2} + 16 x = 42

What are the solutions to the equation -4x^2+4x+15=0 ?
The solutions to the equation -4x^2+4x+15=0 are x=-3/2 ,x= 5/2
Find the zeros of -4x^2+4x+15=0
The zeros of -4x^2+4x+15=0 are x=-3/2 ,x= 5/2