What are the solutions to the equation -3x^2-5x-6=0 ?

The solutions to the equation -3x^2-5x-6=0 are x=-5/6-i(sqrt(47))/6 ,x=-5/6+i(sqrt(47))/6

Find the zeros of -3x^2-5x-6=0

The zeros of -3x^2-5x-6=0 are x=-5/6-i(sqrt(47))/6 ,x=-5/6+i(sqrt(47))/6

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- 3 x^{2} - 5 x - 6 = 0

x = - \frac{5}{6} - i \frac{47}{6}, x = - \frac{5}{6} + i \frac{47}{6}

Solution steps

- 3 x^{2} - 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 3 ) ( - 6 )}{2 ( - 3 )}

Simplify

(- 5)^{2} - 4 (- 3) (- 6) : 47 i

x_{1, 2} = \frac{- ( - 5 ) \pm 47 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 47 i}{2 ( - 3 )}, x_{2} = \frac{- ( - 5 ) - 47 i}{2 ( - 3 )}

x = \frac{- ( - 5 ) + 47 i}{2 ( - 3 )} : - \frac{5}{6} - i \frac{47}{6}

x = \frac{- ( - 5 ) - 47 i}{2 ( - 3 )} : - \frac{5}{6} + i \frac{47}{6}

The solutions to the quadratic equation are:

x = - \frac{5}{6} - i \frac{47}{6}, x = - \frac{5}{6} + i \frac{47}{6}

3^{2} + 1^{2} = c^{2}

d^{2} - 3 d = 0

λ^{2} - 2 λ - 1 = 0

(x^{2} - 2 x + 4) = 0

15 x^{2} - 9 x - 6 = 0

What are the solutions to the equation -3x^2-5x-6=0 ?
The solutions to the equation -3x^2-5x-6=0 are x=-5/6-i(sqrt(47))/6 ,x=-5/6+i(sqrt(47))/6
Find the zeros of -3x^2-5x-6=0
The zeros of -3x^2-5x-6=0 are x=-5/6-i(sqrt(47))/6 ,x=-5/6+i(sqrt(47))/6