What are the solutions to the equation sqrt(3)^2+1^2=c^2 ?

The solutions to the equation sqrt(3)^2+1^2=c^2 are c=2,c=-2

Find the zeros of sqrt(3)^2+1^2=c^2

The zeros of sqrt(3)^2+1^2=c^2 are c=2,c=-2

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3^{2} + 1^{2} = c^{2}

c = 2, c = - 2

Solution steps

(3)^{2} + 1^{2} = c^{2}

Switch sides

c^{2} = (3)^{2} + 1^{2}

Simplify

(3)^{2} + 1^{2} : 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 4, c = - 4

4 = 2

- 4 = - 2

c = 2, c = - 2

d^{2} - 3 d = 0

λ^{2} - 2 λ - 1 = 0

(x^{2} - 2 x + 4) = 0

15 x^{2} - 9 x - 6 = 0

(2 x + 3) (x - 6) = 0

What are the solutions to the equation sqrt(3)^2+1^2=c^2 ?
The solutions to the equation sqrt(3)^2+1^2=c^2 are c=2,c=-2
Find the zeros of sqrt(3)^2+1^2=c^2
The zeros of sqrt(3)^2+1^2=c^2 are c=2,c=-2