What are the solutions to the equation (2x+3)(x-6)=0 ?

The solutions to the equation (2x+3)(x-6)=0 are x=-3/2 ,x=6

Find the zeros of (2x+3)(x-6)=0

The zeros of (2x+3)(x-6)=0 are x=-3/2 ,x=6

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(2 x + 3) (x - 6) = 0

x = - \frac{3}{2}, x = 6

Decimal Notation

x = - 1.5, x = 6

Solution steps

(2 x + 3) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 3 = 0 or x - 6 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x - 6 = 0 : x = 6

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 6

2 x^{2} + x - 6 = 0

0 = 3 x^{2} - 12 x + 4

2 x^{2} + 4 x = 0

x, 12 z^{2} = 4 y^{2} - x^{2}

\frac{x ^{2} - 5 x + 4}{8 - 5} = 5

What are the solutions to the equation (2x+3)(x-6)=0 ?
The solutions to the equation (2x+3)(x-6)=0 are x=-3/2 ,x=6
Find the zeros of (2x+3)(x-6)=0
The zeros of (2x+3)(x-6)=0 are x=-3/2 ,x=6