What are the solutions to the equation (x^2-5x+4)/(8-5)=5 ?

The solutions to the equation (x^2-5x+4)/(8-5)=5 are x=(5+sqrt(69))/2 ,x=(5-sqrt(69))/2

Find the zeros of (x^2-5x+4)/(8-5)=5

The zeros of (x^2-5x+4)/(8-5)=5 are x=(5+sqrt(69))/2 ,x=(5-sqrt(69))/2

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\frac{x ^{2} - 5 x + 4}{8 - 5} = 5

x = \frac{5 + 69}{2}, x = \frac{5 - 69}{2}

Decimal Notation

x = 6.65331 \dots, x = - 1.65331 \dots

Solution steps

\frac{x ^{2} - 5 x + 4}{8 - 5} = 5

Simplify

8 - 5 : 3

\frac{x ^{2} - 5 x + 4}{3} = 5

Multiply both sides by

3

x^{2} - 5 x + 4 = 15

Move

15

to the left side

x^{2} - 5 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 11) = 69

x_{1, 2} = \frac{- ( - 5 ) \pm 69}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 69}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 69}{2 \cdot 1}

x = \frac{- ( - 5 ) + 69}{2 \cdot 1} : \frac{5 + 69}{2}

x = \frac{- ( - 5 ) - 69}{2 \cdot 1} : \frac{5 - 69}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 69}{2}, x = \frac{5 - 69}{2}

3 x^{2} - 5 x = 2 x^{2} + 4 x + 10

5 x^{2} + 12 x - 44 = 0

x^{2} + 1 = 8

x^{2} = 8 - 5 x

0.4048 x^{2} - 60.726 x + 1812.9 = 0

What are the solutions to the equation (x^2-5x+4)/(8-5)=5 ?
The solutions to the equation (x^2-5x+4)/(8-5)=5 are x=(5+sqrt(69))/2 ,x=(5-sqrt(69))/2
Find the zeros of (x^2-5x+4)/(8-5)=5
The zeros of (x^2-5x+4)/(8-5)=5 are x=(5+sqrt(69))/2 ,x=(5-sqrt(69))/2