What are the solutions to the equation x^2=8-5x ?

The solutions to the equation x^2=8-5x are x=(-5+sqrt(57))/2 ,x=(-5-sqrt(57))/2

Find the zeros of x^2=8-5x

The zeros of x^2=8-5x are x=(-5+sqrt(57))/2 ,x=(-5-sqrt(57))/2

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x^{2} = 8 - 5 x

x = \frac{- 5 + 57}{2}, x = \frac{- 5 - 57}{2}

Decimal Notation

x = 1.27491 \dots, x = - 6.27491 \dots

Solution steps

x^{2} = 8 - 5 x

Move

5 x

to the left side

x^{2} + 5 x = 8

Move

8

to the left side

x^{2} + 5 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 8) = 57

x_{1, 2} = \frac{- 5 \pm 57}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 57}{2 \cdot 1}, x_{2} = \frac{- 5 - 57}{2 \cdot 1}

x = \frac{- 5 + 57}{2 \cdot 1} : \frac{- 5 + 57}{2}

x = \frac{- 5 - 57}{2 \cdot 1} : \frac{- 5 - 57}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 57}{2}, x = \frac{- 5 - 57}{2}

0.4048 x^{2} - 60.726 x + 1812.9 = 0

x^{2} - 15 x - 76 = 0

2 p^{2} + 3 = 21

2 x^{2} = - 16

lo g_{4} (4) x^{2} + lo g_{4} (9) = 3

What are the solutions to the equation x^2=8-5x ?
The solutions to the equation x^2=8-5x are x=(-5+sqrt(57))/2 ,x=(-5-sqrt(57))/2
Find the zeros of x^2=8-5x
The zeros of x^2=8-5x are x=(-5+sqrt(57))/2 ,x=(-5-sqrt(57))/2