What are the solutions to the equation 2x^2=-16 ?

The solutions to the equation 2x^2=-16 are x=2sqrt(2)i,x=-2sqrt(2)i

Find the zeros of 2x^2=-16

The zeros of 2x^2=-16 are x=2sqrt(2)i,x=-2sqrt(2)i

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2 x^{2} = - 16

x = 22 i, x = - 22 i

Solution steps

2 x^{2} = - 16

Divide both sides by

2

x^{2} = - 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 8, x = - - 8

- 8 = 22 i

- - 8 = - 22 i

x = 22 i, x = - 22 i

lo g_{4} (4) x^{2} + lo g_{4} (9) = 3

6 x^{2} + 19 x + 4 = 2 x - 1

x, x^{2} - 8 x = 0

2 x^{2} + 8 x + 14 = 0

(x) = x^{2} + x - 6

What are the solutions to the equation 2x^2=-16 ?
The solutions to the equation 2x^2=-16 are x=2sqrt(2)i,x=-2sqrt(2)i
Find the zeros of 2x^2=-16
The zeros of 2x^2=-16 are x=2sqrt(2)i,x=-2sqrt(2)i