What are the solutions to the equation -2x^2+12x-13=0 ?

The solutions to the equation -2x^2+12x-13=0 are x=(6-sqrt(10))/2 ,x=(6+sqrt(10))/2

Find the zeros of -2x^2+12x-13=0

The zeros of -2x^2+12x-13=0 are x=(6-sqrt(10))/2 ,x=(6+sqrt(10))/2

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- 2 x^{2} + 12 x - 13 = 0

x = \frac{6 - 10}{2}, x = \frac{6 + 10}{2}

Decimal Notation

x = 1.41886 \dots, x = 4.58113 \dots

Solution steps

- 2 x^{2} + 12 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 2 ) ( - 13 )}{2 ( - 2 )}

1 2^{2} - 4 (- 2) (- 13) = 210

x_{1, 2} = \frac{- 12 \pm 2 10}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 12 + 2 10}{2 ( - 2 )}, x_{2} = \frac{- 12 - 2 10}{2 ( - 2 )}

x = \frac{- 12 + 2 10}{2 ( - 2 )} : \frac{6 - 10}{2}

x = \frac{- 12 - 2 10}{2 ( - 2 )} : \frac{6 + 10}{2}

The solutions to the quadratic equation are:

x = \frac{6 - 10}{2}, x = \frac{6 + 10}{2}

2 x^{2} - 6 x + \frac{9}{2} = 0

(3 x - 1)^{2} = x^{2} + 21

x^{2} = - x^{2} + 2 x + 4

x^{2} - 40 x + 256 = 0

k^{2} - 6 k + 1 = 0

What are the solutions to the equation -2x^2+12x-13=0 ?
The solutions to the equation -2x^2+12x-13=0 are x=(6-sqrt(10))/2 ,x=(6+sqrt(10))/2
Find the zeros of -2x^2+12x-13=0
The zeros of -2x^2+12x-13=0 are x=(6-sqrt(10))/2 ,x=(6+sqrt(10))/2