What are the solutions to the equation 7x^2=3-5x ?

The solutions to the equation 7x^2=3-5x are x=(-5+sqrt(109))/(14),x=(-5-sqrt(109))/(14)

Find the zeros of 7x^2=3-5x

The zeros of 7x^2=3-5x are x=(-5+sqrt(109))/(14),x=(-5-sqrt(109))/(14)

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7 x^{2} = 3 - 5 x

x = \frac{- 5 + 109}{14}, x = \frac{- 5 - 109}{14}

Decimal Notation

x = 0.38859 \dots, x = - 1.10287 \dots

Solution steps

7 x^{2} = 3 - 5 x

Move

5 x

to the left side

7 x^{2} + 5 x = 3

Move

3

to the left side

7 x^{2} + 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 7 ( - 3 )}{2 \cdot 7}

5^{2} - 4 \cdot 7 (- 3) = 109

x_{1, 2} = \frac{- 5 \pm 109}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 5 + 109}{2 \cdot 7}, x_{2} = \frac{- 5 - 109}{2 \cdot 7}

x = \frac{- 5 + 109}{2 \cdot 7} : \frac{- 5 + 109}{14}

x = \frac{- 5 - 109}{2 \cdot 7} : \frac{- 5 - 109}{14}

The solutions to the quadratic equation are:

x = \frac{- 5 + 109}{14}, x = \frac{- 5 - 109}{14}

n^{2} = 9 n

x^{2} + 3 5^{2} = 3 7^{2}

3 x^{2} + 30 = 0

2 x^{2} + 3 x - 5 = 0

9 x^{2} + 6 x + 10 = 0

What are the solutions to the equation 7x^2=3-5x ?
The solutions to the equation 7x^2=3-5x are x=(-5+sqrt(109))/(14),x=(-5-sqrt(109))/(14)
Find the zeros of 7x^2=3-5x
The zeros of 7x^2=3-5x are x=(-5+sqrt(109))/(14),x=(-5-sqrt(109))/(14)