What are the solutions to the equation 25t^2-10t+1=0 ?

The solutions to the equation 25t^2-10t+1=0 are t= 1/5

Find the zeros of 25t^2-10t+1=0

The zeros of 25t^2-10t+1=0 are t= 1/5

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25 t^{2} - 10 t + 1 = 0

t = \frac{1}{5}

Decimal Notation

t = 0.2

Solution steps

25 t^{2} - 10 t + 1 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 25 \cdot 1}{2 \cdot 25}

(- 10)^{2} - 4 \cdot 25 \cdot 1 = 0

t_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 25}

t = \frac{- ( - 10 )}{2 \cdot 25}

\frac{- ( - 10 )}{2 \cdot 25} = \frac{1}{5}

t = \frac{1}{5}

The solution to the quadratic equation is:

t = \frac{1}{5}

x^{2} - 18 x - 19 = 0

x^{2} = - 2 (2 x + 1)

x^{2} - \frac{3}{4} x = - \frac{1}{4}

8 t^{2} - 64 t + 281 = 0

- 0.5 x^{2} + 15 x = 0

What are the solutions to the equation 25t^2-10t+1=0 ?
The solutions to the equation 25t^2-10t+1=0 are t= 1/5
Find the zeros of 25t^2-10t+1=0
The zeros of 25t^2-10t+1=0 are t= 1/5