What are the solutions to the equation 8t^2-64t+281=0 ?

The solutions to the equation 8t^2-64t+281=0 are t=4+i(3sqrt(34))/4 ,t=4-i(3sqrt(34))/4

Find the zeros of 8t^2-64t+281=0

The zeros of 8t^2-64t+281=0 are t=4+i(3sqrt(34))/4 ,t=4-i(3sqrt(34))/4

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8 t^{2} - 64 t + 281 = 0

t = 4 + i \frac{3 34}{4}, t = 4 - i \frac{3 34}{4}

Solution steps

8 t^{2} - 64 t + 281 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 64 ) \pm ( - 64 ) ^{2} - 4 \cdot 8 \cdot 281}{2 \cdot 8}

Simplify

(- 64)^{2} - 4 \cdot 8 \cdot 281 : 1234 i

t_{1, 2} = \frac{- ( - 64 ) \pm 12 34 i}{2 \cdot 8}

Separate the solutions

t_{1} = \frac{- ( - 64 ) + 12 34 i}{2 \cdot 8}, t_{2} = \frac{- ( - 64 ) - 12 34 i}{2 \cdot 8}

t = \frac{- ( - 64 ) + 12 34 i}{2 \cdot 8} : 4 + i \frac{3 34}{4}

t = \frac{- ( - 64 ) - 12 34 i}{2 \cdot 8} : 4 - i \frac{3 34}{4}

The solutions to the quadratic equation are:

t = 4 + i \frac{3 34}{4}, t = 4 - i \frac{3 34}{4}

- 0.5 x^{2} + 15 x = 0

7 x^{2} - 2 x + 1 = 0

6 x^{2} - 6 x + 4 = 0

24 = x^{2} + 2 x

(x + 8) (x + 5) = 0

What are the solutions to the equation 8t^2-64t+281=0 ?
The solutions to the equation 8t^2-64t+281=0 are t=4+i(3sqrt(34))/4 ,t=4-i(3sqrt(34))/4
Find the zeros of 8t^2-64t+281=0
The zeros of 8t^2-64t+281=0 are t=4+i(3sqrt(34))/4 ,t=4-i(3sqrt(34))/4