What are the solutions to the equation 16x^2-28x+12.25=0 ?

The solutions to the equation 16x^2-28x+12.25=0 are x= 7/8

Find the zeros of 16x^2-28x+12.25=0

The zeros of 16x^2-28x+12.25=0 are x= 7/8

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16 x^{2} - 28 x + 12.25 = 0

x = \frac{7}{8}

Decimal Notation

x = 0.875

Solution steps

16 x^{2} - 28 x + 12.25 = 0

Multiply both sides by

100

1600 x^{2} - 2800 x + 1225 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2800 ) \pm ( - 2800 ) ^{2} - 4 \cdot 1600 \cdot 1225}{2 \cdot 1600}

(- 2800)^{2} - 4 \cdot 1600 \cdot 1225 = 0

x_{1, 2} = \frac{- ( - 2800 ) \pm 0}{2 \cdot 1600}

x = \frac{- ( - 2800 )}{2 \cdot 1600}

\frac{- ( - 2800 )}{2 \cdot 1600} = \frac{7}{8}

x = \frac{7}{8}

The solution to the quadratic equation is:

x = \frac{7}{8}

x (x + 12) = 0

0 = 2 x^{2} + x - 10

X (X + 3) = 5 X + 3

x, x y + x^{2} = 1607

3 y^{2} + 7 y - 7 = 0

What are the solutions to the equation 16x^2-28x+12.25=0 ?
The solutions to the equation 16x^2-28x+12.25=0 are x= 7/8
Find the zeros of 16x^2-28x+12.25=0
The zeros of 16x^2-28x+12.25=0 are x= 7/8