What are the solutions to the equation 17w^2+4w-7=2w^2+6w+1 ?

The solutions to the equation 17w^2+4w-7=2w^2+6w+1 are w= 4/5 ,w=-2/3

Find the zeros of 17w^2+4w-7=2w^2+6w+1

The zeros of 17w^2+4w-7=2w^2+6w+1 are w= 4/5 ,w=-2/3

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17 w^{2} + 4 w - 7 = 2 w^{2} + 6 w + 1

w = \frac{4}{5}, w = - \frac{2}{3}

Decimal Notation

w = 0.8, w = - 0.66666 \dots

Solution steps

17 w^{2} + 4 w - 7 = 2 w^{2} + 6 w + 1

Move

1

to the left side

17 w^{2} + 4 w - 8 = 2 w^{2} + 6 w

Move

6 w

to the left side

17 w^{2} - 2 w - 8 = 2 w^{2}

Move

2 w^{2}

to the left side

15 w^{2} - 2 w - 8 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 15 ( - 8 )}{2 \cdot 15}

(- 2)^{2} - 4 \cdot 15 (- 8) = 22

w_{1, 2} = \frac{- ( - 2 ) \pm 22}{2 \cdot 15}

Separate the solutions

w_{1} = \frac{- ( - 2 ) + 22}{2 \cdot 15}, w_{2} = \frac{- ( - 2 ) - 22}{2 \cdot 15}

w = \frac{- ( - 2 ) + 22}{2 \cdot 15} : \frac{4}{5}

w = \frac{- ( - 2 ) - 22}{2 \cdot 15} : - \frac{2}{3}

The solutions to the quadratic equation are:

w = \frac{4}{5}, w = - \frac{2}{3}

λ^{2} - 9 λ + 18 = 0

x^{2} = 2 4^{2} + 2 6^{2}

(D^{2} + 1) = 0

0 = 3 x^{2} - 9 x - 54

- 9 x^{2} + 18 x + 135 = 0

What are the solutions to the equation 17w^2+4w-7=2w^2+6w+1 ?
The solutions to the equation 17w^2+4w-7=2w^2+6w+1 are w= 4/5 ,w=-2/3
Find the zeros of 17w^2+4w-7=2w^2+6w+1
The zeros of 17w^2+4w-7=2w^2+6w+1 are w= 4/5 ,w=-2/3