What are the solutions to the equation 5x^2-20x+6=0 ?

The solutions to the equation 5x^2-20x+6=0 are x=(10+sqrt(70))/5 ,x=(10-sqrt(70))/5

Find the zeros of 5x^2-20x+6=0

The zeros of 5x^2-20x+6=0 are x=(10+sqrt(70))/5 ,x=(10-sqrt(70))/5

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5 x^{2} - 20 x + 6 = 0

x = \frac{10 + 70}{5}, x = \frac{10 - 70}{5}

Decimal Notation

x = 3.67332 \dots, x = 0.32667 \dots

Solution steps

5 x^{2} - 20 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

(- 20)^{2} - 4 \cdot 5 \cdot 6 = 270

x_{1, 2} = \frac{- ( - 20 ) \pm 2 70}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 2 70}{2 \cdot 5}, x_{2} = \frac{- ( - 20 ) - 2 70}{2 \cdot 5}

x = \frac{- ( - 20 ) + 2 70}{2 \cdot 5} : \frac{10 + 70}{5}

x = \frac{- ( - 20 ) - 2 70}{2 \cdot 5} : \frac{10 - 70}{5}

The solutions to the quadratic equation are:

x = \frac{10 + 70}{5}, x = \frac{10 - 70}{5}

x^{2} - x - 49 = 0

- 2 x^{2} + 44 x - 235

p^{2} + 2 p - 3 = 0

2 x^{2} + 4 x - 32 = 0

x^{2} - 32 x + c

What are the solutions to the equation 5x^2-20x+6=0 ?
The solutions to the equation 5x^2-20x+6=0 are x=(10+sqrt(70))/5 ,x=(10-sqrt(70))/5
Find the zeros of 5x^2-20x+6=0
The zeros of 5x^2-20x+6=0 are x=(10+sqrt(70))/5 ,x=(10-sqrt(70))/5