What are the solutions to the equation -2x^2-20x-50=0 ?

The solutions to the equation -2x^2-20x-50=0 are x=-5

Find the zeros of -2x^2-20x-50=0

The zeros of -2x^2-20x-50=0 are x=-5

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- 2 x^{2} - 20 x - 50 = 0

x = - 5

Solution steps

- 2 x^{2} - 20 x - 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 ( - 2 ) ( - 50 )}{2 ( - 2 )}

(- 20)^{2} - 4 (- 2) (- 50) = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 ( - 2 )}

x = \frac{- ( - 20 )}{2 ( - 2 )}

\frac{- ( - 20 )}{2 ( - 2 )} = - 5

x = - 5

The solution to the quadratic equation is:

x = - 5

4.905 t^{2} - 90 t - 150 = 0

3 x^{2} + 3 = 30

x, 2 x^{2} + 2 y^{2} + 2 x + 2 = 0

15 x^{2} + 24 x + 8 = 0

3 x^{2} + 9 x + 27

What are the solutions to the equation -2x^2-20x-50=0 ?
The solutions to the equation -2x^2-20x-50=0 are x=-5
Find the zeros of -2x^2-20x-50=0
The zeros of -2x^2-20x-50=0 are x=-5