What are the solutions to the equation 15x^2+24x+8=0 ?

The solutions to the equation 15x^2+24x+8=0 are x=(2(sqrt(6)-6))/(15),x=-(2(6+sqrt(6)))/(15)

Find the zeros of 15x^2+24x+8=0

The zeros of 15x^2+24x+8=0 are x=(2(sqrt(6)-6))/(15),x=-(2(6+sqrt(6)))/(15)

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15 x^{2} + 24 x + 8 = 0

x = \frac{2 ( 6 - 6 )}{15}, x = - \frac{2 ( 6 + 6 )}{15}

Decimal Notation

x = - 0.47340 \dots, x = - 1.12659 \dots

Solution steps

15 x^{2} + 24 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 15 \cdot 8}{2 \cdot 15}

2 4^{2} - 4 \cdot 15 \cdot 8 = 46

x_{1, 2} = \frac{- 24 \pm 4 6}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 24 + 4 6}{2 \cdot 15}, x_{2} = \frac{- 24 - 4 6}{2 \cdot 15}

x = \frac{- 24 + 4 6}{2 \cdot 15} : \frac{2 ( 6 - 6 )}{15}

x = \frac{- 24 - 4 6}{2 \cdot 15} : - \frac{2 ( 6 + 6 )}{15}

The solutions to the quadratic equation are:

x = \frac{2 ( 6 - 6 )}{15}, x = - \frac{2 ( 6 + 6 )}{15}

3 x^{2} + 9 x + 27

y, y^{2} = x^{3} (2 - x)

4 x^{2} - 9 x + 20 = 0

12 x^{2} - x = 6

\frac{9}{169} + \frac{y ^{2}}{100} = 1

What are the solutions to the equation 15x^2+24x+8=0 ?
The solutions to the equation 15x^2+24x+8=0 are x=(2(sqrt(6)-6))/(15),x=-(2(6+sqrt(6)))/(15)
Find the zeros of 15x^2+24x+8=0
The zeros of 15x^2+24x+8=0 are x=(2(sqrt(6)-6))/(15),x=-(2(6+sqrt(6)))/(15)